4(x^2+y(y+4))=12x+11

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Solution for 4(x^2+y(y+4))=12x+11 equation: 


Simplifying
4(x2 + y(y + 4)) = 12x + 11

Reorder the terms:
4(x2 + y(4 + y)) = 12x + 11
4(x2 + (4 * y + y * y)) = 12x + 11
4(x2 + (4y + y2)) = 12x + 11
(x2 * 4 + 4y * 4 + y2 * 4) = 12x + 11
(4x2 + 16y + 4y2) = 12x + 11

Reorder the terms:
4x2 + 16y + 4y2 = 11 + 12x

Solving
4x2 + 16y + 4y2 = 11 + 12x

Solving for variable 'x'.

Reorder the terms:
-11 + -12x + 4x2 + 16y + 4y2 = 11 + 12x + -11 + -12x

Reorder the terms:
-11 + -12x + 4x2 + 16y + 4y2 = 11 + -11 + 12x + -12x

Combine like terms: 11 + -11 = 0
-11 + -12x + 4x2 + 16y + 4y2 = 0 + 12x + -12x
-11 + -12x + 4x2 + 16y + 4y2 = 12x + -12x

Combine like terms: 12x + -12x = 0
-11 + -12x + 4x2 + 16y + 4y2 = 0

The solution to this equation could not be determined.

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